Sunday 20 May 2018

FAST CALCULATION TRICK

FAST CALCULATION TRICK

Q- square of 43

We take two base 25 and 50
1. difference from 25 and 43 is 18
2  difference from 50 and 43 is 7 ,so square of 7 is 49
and the ans is 1849



For video CLICK HERE

Thursday 17 May 2018

FAST CALCULATION OF SQUARE TRICK

welcome to SMOKEMATHS ,
now you can watch the trick of fast calculation of fast trick on youtube . its a easy way to find the square of any number.so you can just click here and watch on youtube the fast calculation of square trick

FOR VIDEO CLICK HERE

Wednesday 16 May 2018

FIND THE SQUARE OF ANY NUMBER EASY WAY:-

Now we take a number ,square of 52
we take a method like this 

first we take it like 
we multiple first two number 2 and 2 =4 like
now we do cross multiple of two digit and then add like 2*5+5*2=20 
and take it 0 and 2 carry

we take 0 and carry 2
now we mumtiple last two digit and add carry like 5*5+2=27
so ans is 2704
  


ANOTHER METHOD IS 

WE CHOSE A BASE OF 25
52 IS MORE THEN 27 FROM 25 SO WE TAKE =27 
AND THE SQUARE OF 2 IS 04, SO WE TAKE 04
SO ANS IS 2704


Sunday 13 May 2018

Wednesday 20 September 2017

PROBABILITY ( प्रायिकता )

PROBABILITY- in 1993 A.N. Kolmogrov, a Russian mathematician tried succesfully to relate the theory of probability eith the set theory by axiomatic aproch.


Random variables - A real valued function defined on a sample -space is called a randon - variable .

SAMPLE SPACE- A sample space of a random experiment is the set of all possible outcomes of that experiment and is denoted by S.

  for example- if a coin is tossed then there are two possibilities either we shall get a head or tail . we denoted here head (H) and tail(T).

EXHAUSTIVE EVENTS- All possible outcomes in a trial  are called exhaustive events.

SAMPLE POINT:- Every element of the sample space is called a sample point. and it it is contains finite number of point then its is called finite sample point.for example in a coin H and T.

EVENTS:- Of all the possible outcomes in the sample space of an experiment some outcomes satisfy a specified description , it is called an event and its denoted by E.

CERTAINS AND IMPOSSIBLE EVENTS:- if S is a sample space then S and  Φ are both subset of S and both are events.so S is called certains events and  Φ  is called impossible events.

EQUALLY LIKELY EVENTS:- Two wvents are considered equally likely if one of them cannot ve expected in preference to the other.

EXHAUSTIVE EVENT:- All possible outcomes in a trial are called exhaustive events.
for example :- if we trail a coin then the exhaustive events are H and T.

MUTUALLY EVENT OR INCOMPITIBLE EVENT:- Two or more than two evetns are called Mutually exclusive events if there are no element common to these events . 
if E1 and E2 are two mutually exclusive events then E1 =E2 =Φ 

EXAMPLES :- An experiment in which two coins are tossed together fine the sample space.
solve- S={(H,H) (H,T) (T,T) (T,H)}

IF coins tossed tree times then S ={ (HHH, TTT, THH, HHT, HTT, THT,}

SAMPLE OF COMPOUND EVENTS:- If E contains only one elements of the sample space S then E is called simple events  i.e E= {ei}

compound events :- If E contains more than one elements of the sample space S then S is called compound event. 
 E={ei} where i = 1,2,3....n

FORMULLE FOR PROBABILITY OF AN EVENT:- let E be an event of S containing m element of S ie n(E) = m if P(E) is the probability of the event E happening then P(E) =  n(E) /n(S)

COMPLEMENTARY EVENT:- if E be an event then not happining of the event E is called the complementary event of E and is denoted by E'.

and p(E) + p(E') = 1

Q:- find the probability of throwing on even number with a die.
solve :- let S be a sample space and the event of getting an event number be E then 
                 S ={ 1,2,3,4,5,6} and E={2,4,6} 
                 so n(S) = 6 and n(E) = 3 [ for even number]
       therefore , P(E) =  n(E) /n(S) 
                                 = 3/6
                                 = 1/2
Q:- if two coin tossed , find the chance that there should be heads on both.
solve:-  if two coins tossed then sample space is 
             S={(H,H) (H,T) (T,T) (T,H)}
both head have only one condition that is ( H,H)
therefore P(E) =  n(E) /n(S) 
                       = 1/4

Q:- Find the probability of throwing on even number with die.
solve:-let S be the sample space and the event of getting an even number be E then 
              S = {1,2,3,4,5,6} and E={2,4,6}
              n(S) = 6 and n(E) = 3
              therefore the probability of event of happening  p(E)=n(E)/n(S)
                                                                                                  = 3/6
                                                                                                  =1/2 =ans
COMPOSITION OF EVENTS:-
THE EVENT REPRESENTED BY AUB OR A+B:--  IF the event E happens when A happens or B happens then E is denoted by and E is represented by AUB i.e. E=AUB
THE EVENT REPRESENTED BY A  B OR AB:--If The event E happens when the events A and B both happens then the events E is represented by A  B OR AB i.e. E=A  B 
COMPLEMENT OF EVENT A OR THE EVENT A':--  If the event E happpens when the event A does not happen then E is denoted by A'
Theoram :- If E1 and E2 are any two events then P(E1 U E2) = P(E1)+P(E2)-P(E1 E2).
PROOF:-
lets S be the sample space and n be the number of elements in the events in S. 
let l be the number of elements in E1 and m the number of elements in the events E2 
i.e. n(S)= n   n(E2)= l     n(E2)=m
if the events E1 and E2 are not mutually exclusive then the E1 E2 is not equal to phy.
let n(E1 E2) = r

clearly,    n(E1U E2) = l+m-r

now the probability of E1 and E2 happening denoted by P(E1 E2) is given by  
p(E1U E2) =     
hence proved